9x^2+38x=0

Solution for 9x^2+38x=0 equation:

9x^2+38x=0

a = 9; b = 38; c = 0;
Δ = b2-4ac
Δ = 382-4·9·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-38}{2*9}=\frac{-76}{18}
=-4+2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+38}{2*9}=\frac{0}{18}
=0
$